type cast in initializer

[Hal Peterson]

> >	int	x = 0;
> >	char	*ptr = (char *) &x;
> 
>     In any case, I'm not sure why you'd want to do what your example does,
> since the cast here is a no-op.  

An int pointer does not necessarily have the same format as a char pointer.
Consider a word addressible machine on which the char's are packed into the
words.
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Hal Peterson / Cray Research / 1440 Northland Dr. / Mendota Hts, MN  55120
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