printf() problem

[John Durko]

In article <11657 at hodge.UUCP>, jdm at hodge.UUCP (jdm) writes:
>     Perhaps someone could explain this printf() phenomena to me.
>
>     printf("%x %x %x %x\n", getc(fp), getc(fp), getc(fp), getc(fp));
>
>     Although the order of the data in the file is:
>
>         92 AB 4E 33
> 
>     printf() displays it as:
> 
>         33 4E AB 92

The problem here ( I think :-} ) is that the compiler is pushing the function 
arguments on the stack from right to left. Therefore the last argument on the
list is the first to be evaluated and the thus makes the first call
to getc(). 


The following code illustrates this:

#include <stdio.h>

main(){

	int i = 1;

	printf(" %d  %d  %d  %d  \n",i++,i++,i++,i++);

}

Compiled and run this produces 4 3 2 1 .

Can anybody tell me if this behavoir is "guaranteed" in C.  I know that each
argument expression must be evaluated fully before the next but could find
no "guarantee" on the order that it is done.

-- 
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   /  / /  / /    /  /|  / /      John Durko, Boeing Canada, Toronto.
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