C problems

[Leslie Mikesell]

In article <13566 at haddock.ima.isc.com> karl at haddock.ima.isc.com (Karl Heuer) writes:
>>char **argv;      /* since you are learning it may be easier to understand
>>                     this syntax better by defining it as:  char *argv[]  */

>On the other hand, since this use of [] is a special case which exists nowhere
>else in the language (it works *only* for formal arguments), it may be less
>confusing to stick with "char **argv" after all.

Umm, isn't that the same as:

char *list[] = {
                "one",
                "two",
                "three",
                 0 };

which seems to work as a global definition.  Argv is something similar
so the char *argv[]; declaration makes sense.

Les Mikesell