Problem with ()?():() as ending test in for-loop
Gary L. Randolph
randolph at ektools.UUCP
Fri May 26 00:02:25 AEST 1989
In article <1917 at ektools.UUCP> randolph at ektools.UUCP (Gary L. Randolph) writes:
>In article <20658 at news.Think.COM> barmar at kulla.think.com.UUCP (Barry Margolin) writes:
>>In article <1200 at liszt.kulesat.uucp> vanpetegem at liszt.kulesat.uucp writes:
>>>The code with which I am in trouble, goes as follows:
>>>
>>> for(n = 1; ((n % 10) ? (k > 2) : (n < 100)); n++)
>>> ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
>>> {
>>> ..... (in some expressions k is changed, depending on n)
>>> }
>>>What I want to do is simply perform the test (k > 2) as ending test for the
>>>"for-loop", except in the cases where n is dividable by 10. In the latter
>>>situation the test (n < 100) has to be done.
>
=The sense of the test clause of your :? expression is wrong. When n
=is divisible by 10, (n % 10) is 0, and 0 represents "false" in C. I
=would write your end test as
= ((n % 10) == 0) ? (k > 2) : (n < 100)
=i.e. they would just interchange the true and false clauses, taking
=advantage of the fact that the result of the % can be used as a
=boolean.
My original anwer has some problems - PLEASE ignore it...
Here is, I believe, a correct answer.
NOOOOO! I do NOT think your logic is wrong. I am sure it is correct
according to your explanation of what you want to do. There *is* a
problem however...
...Stuff here is too wrong (embarrASSing) for me to repeat...
You don't mention whether variable k was initialized before
entering the for. IT SHOULD BE.
I ran a short test as follows:
main()
{
int n;
float k = 6;
for(n=1;((n % 10) ? (k>2) : (n<100)); n++)
{
k -= 2;
}
printf("n: %d\n k: %f\n",n,k);
}
This produced the expected result:
n: 3
k: 2.000000
I hope THIS helps...
--Gary Randolph
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