Pointers, Structs, and Arrays

[Larry Jones]

In article <743 at mccc.UUCP>, pjh at mccc.UUCP (Pete Holsberg) writes:
> struct foo
> {
> 	char bar[20];
> } list[100];
> 
> 		*list[i].bar = '\0';
> 
> Now I know that the last line points to the first character in the bar array
> In each struct variable, but how?  If bar = &bar[0], how so the '*' and the
> '&' "get together" to make the last line equivalent to
> 		list[i].bar[0]

Well, the problem is that bar is NOT equivalent to &bar[0].
Rather, list[i].bar is equivalent to &list[i].bar[0], which
should make it easier to see how the "*" and the "&" get
together.

What you have to realize is that bar DOES NOT EXIST -- since it
is a member of a structure, it only exists as part of an actual
instance of the structure and must be referenced as such.
----
Larry Jones                         UUCP: uunet!sdrc!scjones
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