initialization

[Chris Torek]

In article <11221 at odin.corp.sgi.com> jindak at surfside.sgi.com
(Chris Schoeneman) writes:
(re the code `f(int a) { int i = a, j = i + 1;')

>... don't worry, the comma operator is evaluated left to right.  So your
>code will always work correctly (i.e. "a" will be assigned to "i", then
>"i"+1 will be assigned to "j").

Strictly speaking, the comma in

	int i = a, j = i + 1;

is not a comma operator.  Nonetheless the ANSI C standard guarantees
that, after the sequence point at the semicolon, `i' will have the
value `a' has and `j' will have the result of `a + 1' (since i==a, i+1
has the same effect as a+1, including such things as runtime traps, at
least if overflow is `implementation defined' [I cannot remember
whether this is in fact the case]).
-- 
In-Real-Life: Chris Torek, Univ of MD Comp Sci Dept (+1 301 454 7163)
Domain:	chris at cs.umd.edu	Path:	uunet!mimsy!chris