Using sizeof() on a parameter array

[Dale Worley]

In article <12151 at jarthur.Claremont.EDU> jseidman at jarthur.Claremont.EDU (Jim Seidman) writes:
   void test(char param[80]) {
       char local[80];

   }

Yes, the type of 'param' is 'char *'.  See section 3.7.1 of the ANSI
standard.  This makes is hard to pass arrays as arguments.  However,
if you wrap the array in a struct, the array will be passed as
requested!

    struct dummy {
	    char a[80];
    };

    void test(struct dummy param) {
	    printf("sizeof(param) = %d\n", sizeof(param));
    }

will print 80 as expected!

Dale

Dale Worley		Compass, Inc.			worley at compass.com
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