A question about the tertiary (? : ) operator

[John F. Haugh II]

In article <612 at cybaswan.UUCP> iiitsh at cybaswan.UUCP (Steve Hosgood) writes:
>I never noticed until last night that the conditional operator:
>
><condition>? <val1>: <val2>
>
>..is not a valid lvalue, even if both <val1> and <val2> are lvalues!
>I wanted to say:
>
>(flag > 0? foo: bar) = <complex expression>;
>
>..which didn't work, needless to say. I had to employ a temporary variable
>and an 'if' statement in the end :-(.

There is a way to do this ...

	*((type_of_foobar *) flag > 0 ? &foo:&bar) = <complex expression>
-- 
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