Function Argument Evaluation

[Ed Gould]

>I would be very interested in seeing a program whose behavior
>was *not* undefined, yet could arbitrarily produce either of two
>drastically different outputs depending solely on the unspecified
>order of evaluation.

Will this do?

	foo() {
		int v = 1;

		printf("%d %d\n", v, ++v);
	}

It may print either

	1 2
or
	2 2

depending solely on order of evaluation.  Are there any other
things here that make this program's behavior undefined?  I
think not.

-- 
Ed Gould                    mt Xinu, 2560 Ninth St., Berkeley, CA  94710  USA
ed at mtxinu.COM		    +1 415 644 0146

"I'll fight them as a woman, not a lady.  I'll fight them as an engineer."