Function Argument Evaluation

[Dik T. Winter]

In article <17868 at crdgw1.crd.ge.com> volpe at camelback.crd.ge.com (Christopher R Volpe) writes:
 > In article <1991Mar23.014442.24307 at cs.ucla.edu>, jon at maui.cs.ucla.edu
 > (Jonathan Gingerich) writes:
 > |>don't see how this affects the value of (p=&x) and (p=&y) which would 
 > |>remain &x and &y (given the correct type of p).
 > Ditto, again.
You both fail to see that the value of
	(lvalue = expression)
is *not* the value of 'expression' before assignment but the value of 'lvalue'
after assignment.
--
dik t. winter, cwi, amsterdam, nederland
dik at cwi.nl