Parity error in PC6300

[george.p.wilkin]

>From article <4580 at alvin.mcnc.org>, by somers at mcnc.org (Robert W. Somers):
> 	Where is ( are ) the following locations:
> 
> 		0D:8000:0000:0106:0104
> 		0D:8000:0000:010A:0108
> 		0D:8000:0000:0100:0152

I need to know the following:
where is your ram and which bank holds what????
is bank 0 with 512k or is bank 1 with 512K
is bank ?? with 128K ??

you're missing some info(and so am I) but here's what I know


nnn KB ram fail:cc:y000:zzzz:wwww:rrrr
                
cc= ram config
    01 128K total (128K bank 0, bank 1 empty)
    02 256K total (128K bank 0, 128K bank 1)
    03 512K total (128K bank 0, 128K bank 1, 256K on exp board)
    0? 512K total (512K bank 0)
    05 640K total (128K bank 0, 128K bank 1, 384K on exp board)
    0? 640K total (128K bank 0, 512K bank 1)
    0D 640K total (512K bank 0, 128K bank 1) ??????????

y = bank failed
    1= bank 0 128K (for 64k dram )
    2= bank 1 128K (for 64k dram )
    3= bank 0 exp 128K (for 64k dram )
    4= bank 1 exp 128K (for 64k dram )
    5= bank 2 exp 128K (for 64k dram )
    ?= bank 1 row a (for 256K dram)
    ?= bank 1 row b (for 256K dram)
    8= bank 1 row a (for 256K dram)
    ?= bank 1 row b (for 256K dram)

000 = segment failure 

zzzz = offset

wwww = data written

rrrr = data read

Also note I think the 128K segmant map to existing ram regardless of conf.

in a 640K machine with 512K in bank1 an error of 5(128K,bank 2 expansion )
would map to the last row of memory bank 1 with the proper offset added in.

george
-- 
George Wilkin 	AT&T Network Systems,(IH MAIN BL)
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