Bourne shell question

[Conor P. Cahill]

In article <1943 at sactoh0.UUCP>, jak at sactoh0.UUCP (Jay A. Konigsberg) writes:

> 
> When the pipe into " pg " is removed it works ok, but I would like
> to keep the pg in the script.

Your problem is that pg always exits with a 0 (at least I could not get
any non-zero exit) and therefore the stuff to the right of the  || will never
be executed.  You could do the following:

(ls -l | grep "^d" || echo "There are no subdirectories" ) | pg

or you could re-write the script so it used more than 1 line:

	ls -l | grep "^d" > /tmp/sh$$

	if [ $? = 0 ]; then
		pg /tmp/sh$$
	else
		echo "There are no ..."
	fi

	rm /tmp/sh$$

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