Hacking

[Wailin' Through The Nets]

I seem to recall pkr at sgi.com (Phil Ronzone) saying:
>
>Well, assuming 100,000 words of 13 characters each, for each of 4096
>possibilities, that gives us 5,324,800,000 bytes. Now, with the
>750MB and 1.2G 5.25" disk drives around, I'd probably have to have
>several of the drives, OR, maybe use a smaller dictionary.
>
>100,000 words is a LOT of words .....
>
Don't be silly.  Talk about 25000 words x 4096 permutations x 13 bytes.
That gives you 1.3 x 10^9 bytes.  Now figure this is all ascii and you
can expect at least 50% compression ratios.  So say 6.6 x 10^8 bytes.
That'll fit on my gigabyte drive with room to spare.  Wanna tell me that
the NSA _doesn't_ have this kind of thing precomputed?

-- 
The Wailer at the Gates of Dawn		     | johnv at metaware.com           |
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