sbrk inertia - (nf)

[utzoo!decvax!cca!ima!johnl]

#R:p500vax:-18000:ima:13500001:000:352
ima!johnl    Mar 25 11:46:00 1983

The behavior of sbrk() noted is correct.  It returns the old (not the new)
break value so you have the beginning (not the end) of the chunk of
storage allocated.

John Levine, decvax!yale-co!jrl, ucbvax!cbosgd!ima!johnl,
{research|alice|rabbit|amd70}!ima!johnl

PS:  This particular fact is clearly documented in the obvious place in
the manual.  Bah.