UNIX v7 calling sched()

[George Miler]

     I am working on a project at NC State University involving porting
UNIX Version 7 to a 68000 based machine.  I have reached a point where
a few things are a bit unclear to me.

     In function main(), the internal inits are done and newproc is
called to set up "/etc/init".  Once this is done, main() returns and
the code in start.s does a return from interrupt to get things going.
What I don't understand is how sched() gets going.  The sched() function
is called if newproc() does not create the init process, followed by
main() returning.  But, of course, we need /etc/init so that is done.


  main ()
  {
    ......
    if (newproc())      <====   true, create /etc/init process
    {
      copy (/etc/init)
      return;           <====   exit main, starts copied process
    }
    sched ();           <====   never reached if did /etc/init
  }

     Any help or explanation you are able to send me will be greatly
appericated.

						George Miler
						miler at adm.csc.ncsu.edu

-- 
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
George B. Miler                           North Carolina State University
miler at adm.csc.ncsu.edu          {decvax, gatech}!mcnc!ncsuvx!cscadm!miler
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=